For sensitivity, we assume an animal is infected and that it is tested with both Test 1 and Test 2. For Test 1, the probability of a positive test result (given that the animal is infected) is Se<sub>1</sub> = 0.5 and the corresponding probability that it will give a negative result is 1 – Se<sub>1</sub>, also = 0.5 for this example. For Test 2, the probability of a positive test result (given that the animal is infected) is Se<sub>2</sub> = 0.6 and the corresponding probability that it will give a negative result is 1 – Se<sub>2</sub> = 0.4.
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For sensitivity, we assume an animal is infected and that it is tested with both Test 1 and Test 2. For Test 1, the probability of a positive test result (given that the animal is infected) is Se<sub>1</sub> = 0.5 and the corresponding probability that it will give a negative result is 1 - Se<sub>1</sub>, also = 0.5 for this example. For Test 2, the probability of a positive test result (given that the animal is infected) is Se<sub>2</sub> = 0.6 and the corresponding probability that it will give a negative result is 1 - Se<sub>2</sub> = 0.4.
Revisi terkini pada 10 Mei 2015 14.44
For sensitivity, we assume an animal is infected and that it is tested with both Test 1 and Test 2. For Test 1, the probability of a positive test result (given that the animal is infected) is Se1 = 0.5 and the corresponding probability that it will give a negative result is 1 - Se1, also = 0.5 for this example. For Test 2, the probability of a positive test result (given that the animal is infected) is Se2 = 0.6 and the corresponding probability that it will give a negative result is 1 - Se2 = 0.4.