https://wiki.isikhnas.com/index.php?action=history&feed=atom&title=Translations%3AAdvanced_Field_Epi%3AManual_2_-_Diagnostic_Tests%2F72%2Fen 2026-08-19T09:54:51Z Revision history for this page on the wiki MediaWiki 1.31.16 https://wiki.isikhnas.com/index.php?title=Translations:Advanced_Field_Epi:Manual_2_-_Diagnostic_Tests/72/en&diff=36984&oldid=prev 2015-05-10T07:42:48Z

<p>Importing a new version from external source</p> <table class="diff diff-contentalign-left" data-mw="interface"> <col class="diff-marker" /> <col class="diff-content" /> <col class="diff-marker" /> <col class="diff-content" /> <tr class="diff-title" lang="id"> <td colspan="2" style="background-color: #fff; color: #222; text-align: center;">← Revisi sebelumnya</td> <td colspan="2" style="background-color: #fff; color: #222; text-align: center;">Revisi per 10 Mei 2015 07.42</td> </tr><tr><td colspan="2" class="diff-lineno" id="mw-diff-left-l1" >Baris 1:</td> <td colspan="2" class="diff-lineno">Baris 1:</td></tr> <tr><td class='diff-marker'>−</td><td style="color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #ffe49c; vertical-align: top; white-space: pre-wrap;"><div>For parallel interpretation, the result is considered positive if either of the individual test results is positive. Alternatively, for a result to be considered negative both test results must be negative. Again this can be determined from the scenario tree, where the limb on the right represents both tests having a negative result and the probability of both negative results is P(<del class="diffchange diffchange-inline">–</del>/<del class="diffchange diffchange-inline">–</del>) = (1 <del class="diffchange diffchange-inline">– </del>Se&lt;sub&gt;1&lt;/sub&gt;) ï‚´ (1 <del class="diffchange diffchange-inline">– </del>Se&lt;sub&gt;2&lt;/sub&gt;). Therefore the probability of an overall positive result for parallel interpretation is Se&lt;sub&gt;parallel&lt;/sub&gt; = 1 <del class="diffchange diffchange-inline">– </del>(1 <del class="diffchange diffchange-inline">– </del>Se&lt;sub&gt;1&lt;/sub&gt;) ï‚´ (1 <del class="diffchange diffchange-inline">– </del>Se&lt;sub&gt;2&lt;/sub&gt;) = 0.8 (80%) for this example.</div></td><td class='diff-marker'>+</td><td style="color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;"><div>For parallel interpretation, the result is considered positive if either of the individual test results is positive. Alternatively, for a result to be considered negative both test results must be negative. Again this can be determined from the scenario tree, where the limb on the right represents both tests having a negative result and the probability of both negative results is P(<ins class="diffchange diffchange-inline">-</ins>/<ins class="diffchange diffchange-inline">-</ins>) = (1 <ins class="diffchange diffchange-inline">- </ins>Se&lt;sub&gt;1&lt;/sub&gt;) ï‚´ (1 <ins class="diffchange diffchange-inline">- </ins>Se&lt;sub&gt;2&lt;/sub&gt;). Therefore the probability of an overall positive result for parallel interpretation is Se&lt;sub&gt;parallel&lt;/sub&gt; = 1 <ins class="diffchange diffchange-inline">- </ins>(1 <ins class="diffchange diffchange-inline">- </ins>Se&lt;sub&gt;1&lt;/sub&gt;) ï‚´ (1 <ins class="diffchange diffchange-inline">- </ins>Se&lt;sub&gt;2&lt;/sub&gt;) = 0.8 (80%) for this example.</div></td></tr> </table>

FuzzyBot https://wiki.isikhnas.com/index.php?title=Translations:Advanced_Field_Epi:Manual_2_-_Diagnostic_Tests/72/en&diff=7886&oldid=prev 2014-08-25T03:40:42Z

<p>Importing a new version from external source</p> <p><b>Halaman baru</b></p><div>For parallel interpretation, the result is considered positive if either of the individual test results is positive. Alternatively, for a result to be considered negative both test results must be negative. Again this can be determined from the scenario tree, where the limb on the right represents both tests having a negative result and the probability of both negative results is P(–/–) = (1 – Se&lt;sub&gt;1&lt;/sub&gt;)  (1 – Se&lt;sub&gt;2&lt;/sub&gt;). Therefore the probability of an overall positive result for parallel interpretation is Se&lt;sub&gt;parallel&lt;/sub&gt; = 1 – (1 – Se&lt;sub&gt;1&lt;/sub&gt;)  (1 – Se&lt;sub&gt;2&lt;/sub&gt;) = 0.8 (80%) for this example.</div>

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